RSA
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- Choose two large, distinct primes p and q, and let n = pq.
- Select an integer e so that gcd(e, (p-1)(q-1)) = 1, 1 < e < (p-1)(q-1)
- Solve ed ≡ 1 ( mod (p-1)(q-1) ) for d.
Public key = (e, n) Private key = (d, n)
For message M < n,
C ≡ M^e (mod n) C is the cyphertext
R ≡ C^d (mod n) R is the original message